Chemistry - Solid State Question with Solution | TestHub

$\text{58}\text{.5}\text{g}$$\mathrm{N}\mathrm{a}\mathrm{C}\mathrm{l}=6\times 10^{23}$molecule (atoms) of$\mathrm{N}\mathrm{a}\mathrm{C}\mathrm{l}$(as$\mathrm{N}\mathrm{a}\mathrm{C}\mathrm{l}$occupies FCC system)
1-unit cell have 4 molecules of$\mathrm{N}\mathrm{a}\mathrm{C}\mathrm{l}$
So, no. of unit cell$=\frac{6\times 10^{23}}{4}=1.5\times 10^{23}$