Chemistry - Solid State Question with Solution | TestHub

Number of${\mathrm{O}}^{2-}$ions = n
Number of tetrahedral voids = 2n
Number of octahedral voids = n
Number of X ions$=\frac{2\mathrm{n}}{5}$
Number of Y ions$=\frac{\mathrm{n}}{2}$
$\left.\begin{array}{l}\text{X}\text{:}\text{Y}\text{:}\text{O}\\ \frac{\text{2n}}{\text{5}}\text{:}\frac{\text{n}}{\text{2}}\text{:}\text{n}\\ \text{4}\text{:}\text{5}\text{:}\text{10}\end{array}\right\}$
Simplest formula$={\mathrm{X}}_4{\mathrm{Y}}_5{\mathrm{O}}_{10}$.