Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StatePacking in lonic SolidsMedium2 minPYQ_2008

ChemistryMediumsingle choice

The number of formula units of calcium flouride $CaF_{2}$ present in $146.4 g$ of $CaF_{2}$ are (molar mass of $CaF_{2}$ is $78.08 g / mol$ )

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Answer:

Solution:

Formula unit $=$ no. of molecules of $CaF_{2}$ . $Moles = \frac{massin gm}{molar mass} = \frac{146.4 gm}{78.08 gm} = 1.875 Molecules = Mole \times 6.022 \times 1 0^{23} = 1.875 \times 6.022 \times 1 0^{23} = 1.129 \times 1 0^{24} units of CaF_{2}$

Stream:VITEEESubject:ChemistryTopic:Solid StateSubtopic:Packing in lonic Solids

⏱ 2mℹ️ Source: PYQ_2008

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