Copper has face centered cubic (fcc) lattice with interatomic spacing equal to 2.54 A ˚ . The value of lattice constant for this lattice is:NEET 2005

Given 2 π = 2.54 A ˚ ⇒ r = 2 2.54 = 1.27 A ˚ For fcc lattice: r a = 2 2 a = r 2 2 = 1.27 × 2 × 1.44 = 3.59 A ∘

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Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StateCubic CrystalsMedium2 minPYQ_2005

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Copper has face centered cubic (fcc) lattice with interatomic spacing equal to $2.54 \overset{˚}{A}$ . The value of lattice constant for this lattice is:NEET 2005

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Solution:

Given $2 π = 2.54 \overset{˚}{A}$ $\Rightarrow r = \frac{2.54}{2} = 1.27 \overset{˚}{A}$ For fcc lattice: $r a = \frac{a}{2 2} = r 22 = 1.27 \times 2 \times 1.44 = 3.59 A^{\circ}$

Stream:NEETSubject:ChemistryTopic:Solid StateSubtopic:Cubic Crystals

⏱ 2mℹ️ Source: PYQ_2005

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