Match the reactions in Column I with the type(s) of reaction in Column II on the basis of oxidation/reduction. Column I Column II A) 3CaO + 2P₂O₅ → Ca₃(PO₄)₂ P) Disproportionation B) 2Cu⁺ → Cu + Cu²⁺

Question

Match the reactions in Column I with the type(s) of reaction in Column II on the basis of oxidation/reduction.

Column I	Column II
A) 3CaO + 2P₂O₅ $\to$ Ca₃(PO₄)₂	P) Disproportionation
B) 2Cu⁺ $\to$ Cu + Cu²⁺	Q) Comproportionation
C) NH₄NO₂ $\to$ N₂ + 2H₂O	R) Non-redox
D) CH₄ + 2O₂ $\to$ CO₂ + 2H₂O	S) Combustion
	T) Redox

TestHub · Accepted Answer

(A) Ca stays +2, P stays +5, O stays -2, so no electron transfer: non-redox (R). (B) Cu⁺ goes to both Cu(0) and Cu²⁺; one species is both oxidized and reduced: disproportionation (P), hence redox (T). (C) N at -3 (NH₄⁺) and +3 (NO₂⁻) both go to N₂(0); two species combine to one oxidation state: comproportionation (Q), hence redox (T). (D) Burning of methane in O₂: combustion (S) with C going -4 to +4, so redox (T).

Chemistry - Redox Reactions Question with Solution | TestHub

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