Chemistry - Redox Reactions Question with Solution | TestHub

Normality of $3\%{\mathrm{Na}}_2{\mathrm{CO}}_3$ $\mathrm{N}=\frac{3\times 1000}{53\times 100}=0.566\mathrm{N}$ For ${\mathrm{H}}_2{\mathrm{SO}}_4$ sol. ${\mathrm{N}}_1=0.1,{\mathrm{V}}_1=100\mathrm{mL}$ For ${\mathrm{Na}}_2{\mathrm{CO}}_3$ sol. ${\mathrm{N}}_2=0.566$ Now apply ${\mathrm{N}}_1{\mathrm{V}}_1={\mathrm{N}}_2{\mathrm{V}}_2$ ${\mathrm{V}}_2=\frac{{\mathrm{N}}_1{\mathrm{V}}_1}{{\mathrm{N}}_2}=\frac{0.1\times 1000\mathrm{mL}}{0.566}=176.66\mathrm{mL}$