Chemistry - Redox Reactions Question with Solution | TestHub
ChemistryRedox ReactionsProblem involving Equivalent ConceptMedium2 minQB
ChemistryMediumnumerical
V litre of SO₂ at 0°C and 1 atm is required to reduce 16.9 g of HClO₃ to HCl. The number of moles in '5 V' litre of SO₂ at 273°C and 2 atm is
Answer:
3.00
Solution:
HClO₃: 16.9/84.5 = 0.2 mol; Cl goes +5 -1 (6e each), so 1.2 mol e⁻. SO₂ SO₄²⁻ gives 2e per mol, so SO₂ = 0.6 mol and V = 0.6 × 22.4 = 13.44 L. Then 5V = 67.2 L at 273°C, 2 atm: n = PV/RT = 2 × 67.2/0.0821 × 546 = 134.4/44.83 ≈ 3. Ans: 3.
Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Problem involving Equivalent Concept
⏱ 2mℹ️ Source: QB
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