Chemistry - Redox Reactions Question with Solution | TestHub

For $\mathrm{Xe}{\mathrm{F}}_{\mathrm{n}}$: 131/131 + 19n = 0.775 $\Rightarrow$ 131 + 19n ≈ 169 $\Rightarrow$ $n$ = 2, so the compound is $\mathrm{Xe}{\mathrm{F}}_2$. With F = -1, Xe = +2. Hence (c).