Chemistry - Redox Reactions Question with Solution | TestHub

E = 71 = M/1, so n-factor = 1: per mole $\mathrm{C}{\mathrm{l}}_2$ only $1{\mathrm{e}}^{-}$ is transferred, i.e. one Cl atom gains 1e (to $\mathrm{C}{\mathrm{l}}^{-}$) and the other loses 1e. The oxidized product is $\mathrm{Cl}{\mathrm{O}}^{-}$ (hypochlorite): $\mathrm{C}{\mathrm{l}}_2$ + $2O{\mathrm{H}}^{-}$ $\to$ $\mathrm{C}{\mathrm{l}}^{-}$ + $\mathrm{Cl}{\mathrm{O}}^{-}$ + ${\mathrm{H}}_2\mathrm{O}$. O.S. of Cl in $\mathrm{Cl}{\mathrm{O}}^{-}$ = +1. Ans: 1.