Chemistry - Redox Reactions Question with Solution | TestHub
ChemistryRedox ReactionsEquivalent Weight and n-factorEasy2 minQB
ChemistryEasysingle choice
A sample of a metal carbonate MCO₃ was neutralized by 10 ml of 0.1 N HCl and the resulting chloride gave 0.0517 g of phosphate, M₃(PO₄)₂. The equivalent weight of M is
Options:
Answer:
A
Solution:
meq HCl = 10 x 0.1 = 1 meq, so MCO₃ = 1 meq = 0.5 mmol and M²⁺ = 0.5 mmol. mol M₃(PO₄)₂ = 0.5/3 = 0.1667 mmol; molar mass = 0.0517/0.1667 x 1000 = 310.2 = 3M + 2(95), so M = 40.06. Equivalent weight = 40.06/2 = 20.03, option (a).
Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Equivalent Weight and n-factor
⏱ 2mℹ️ Source: QB
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