Chemistry - Redox Reactions Question with Solution | TestHub

In the reaction of ${\mathrm{S}}_2{\mathrm{O}}_3{}^{2-}$ with ${\mathrm{I}}_2$, oxidation state of sulphur changes to +2 to +2.5 In the reaction of ${\mathrm{S}}_2{\mathrm{O}}_3{}^{2-}$ with ${\mathrm{Br}}_2$, oxidation state of sulphur changes from +2 to +6 . $\therefore$ Both ${\mathrm{I}}_2$ and ${\mathrm{Br}}_2$ are oxidant (oxidising agent) and ${\mathrm{Br}}_2$ is stronger oxidant than ${\mathrm{I}}_2$.