Chemistry - Redox Reactions Question with Solution | TestHub

No. of equivalents of ${\mathrm{H}}_2{\mathrm{SO}}_4=\mathrm{M}\times \mathrm{V}\times \mathrm{n}-\mathrm{factor} = 100\times 0.1\times 2=20$

No. of equivalents of $\mathrm{NaOH}=50\times 0.1=5$

No. of equivalents of ${\mathrm{H}}_2{\mathrm{SO}}_4$ left $=20-5=15$

$\Rightarrow 150\times x=15$

$\mathrm{x}=\frac{1}{10}=0.1 \mathrm{N}=1\times {10}^{-1} \mathrm{N}$