Chemistry - Redox Reactions Question with Solution | TestHub

millimoles of oxalic acid$=50\times 0.5$

milli equivalent of oxalic acid$=50\times 0.5\times 2$

millimoles of$\mathrm{NaOH}=25\times \mathrm{M}=$milli equivalent of$\mathrm{NaOH}$

$\therefore 50\times 0.5\times 2=25\times \mathrm{M}$

$\Rightarrow \mathrm{M}=2$

$\mathrm{M}=2$so,$1000\text{ml}$$\mathrm{NaOH}$solution contains

$=2\text{ mol of }\mathrm{NaOH}$

$=2\times 40=80\text{g }\mathrm{NaOH}$

$\therefore 50\text{ml }\mathrm{NaOH}$solution contains$=\frac{80}{1000}\times 50=4 \text{g}$