The virial form of van der Waal's gas equation is PV = RT(1 + B/V + C/V 2 + …) = RT(1 + B'P + C'P 2 + …). The second virial coefficient of argon gas at 262.5 K is -1 l mol -1 . What is

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The virial form of van der Waal's gas equation is PV = RT(1 + B/V + C/V 2 + …) = RT(1 + B'P + C'P 2 + …). The second virial coefficient of argon gas at 262.5 K is -1 l mol -1 . What is the density of argon gas at 262.5 K and 1 atm? Neglect all the terms after second term in the virial forms, under these condition. (R = 0.08 L-atm/K-mol, Ar = 40)

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Using the pressure form truncated after the second term, PV = RT(1 + B'P) with B' = B/(RT): V = (RT)/P + B = (0.08 × 262.5) - 1 = 21 - 1 = 20 l per mole. Density = 40/20 = 2.0 g/l. Ans: (a)

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