The equation of state for a van der Waal gas can be expressed as Z = 1 + B/Vₘ + C/Vₘ² + .... If the van der Waal constants a and b are 1.4784 litre² atm/mol² and 0.04 litre mol⁻¹, respectively, then t

Question

The equation of state for a van der Waal gas can be expressed as Z = 1 + B/Vₘ + C/Vₘ² + .... If the van der Waal constants a and b are 1.4784 litre² atm/mol² and 0.04 litre mol⁻¹, respectively, then the value of second virial coefficient (in litre/mol) for nitrogen gas at 27°C is

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Answer:

A

Solution:

B = b - a/(RT). At 300 K: a/(RT) = 1.4784/(0.0821 × 300) = 1.4784/24.63 = 0.06 l mol⁻¹. So B = 0.04 - 0.06 = -0.02 l/mol. Ans: (a)

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B = b - a/(RT). At 300 K: a/(RT) = 1.4784/(0.0821 × 300) = 1.4784/24.63 = 0.06 l mol⁻¹. So B = 0.04 - 0.06 = -0.02 l/mol. Ans: (a)

Chemistry - Real Gas Question with Solution | TestHub

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