The virial form of van der Waal's gas equation is PV = RT(1 + B/V + C/V² + …) = RT(1 + B'P + C'P² + …). The second virial coefficient of carbon dioxide gas at 275 K is -2 l mol⁻¹. What

Question

The virial form of van der Waal's gas equation is PV = RT(1 + B/V + C/V² + …) = RT(1 + B'P + C'P² + …). The second virial coefficient of carbon dioxide gas at 275 K is -2 l mol⁻¹. What is the density of carbon dioxide gas at 275 K and 1 atm? Neglect all the terms after second term in the virial forms, under these condition. (R = 0.08 L-atm/K-mol, CO₂ = 44)

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Answer:

C

Solution:

Using the truncated pressure form, PV = RT(1 + B'P) with B' = B/(RT): V = (RT)/P + B = (0.08 × 275) - 2 = 22 - 2 = 20 l per mole. Density = 44/20 = 2.2 g/l. Ans: (c)

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Using the truncated pressure form, PV = RT(1 + B'P) with B' = B/(RT): V = (RT)/P + B = (0.08 × 275) - 2 = 22 - 2 = 20 l per mole. Density = 44/20 = 2.2 g/l. Ans: (c)

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