The second virial coefficient of methane can be approximated by the empirical equation:
B = a + b·e^−c/T²
where a = -0.2 bar^-1, b = 0.22 bar^-1, and c = 950 K². What is the value of the Boyle temperature of methane (in K)? (ln 1.1 = 0.095)

Question

The second virial coefficient of methane can be approximated by the empirical equation:

B = a + b·e^−c/T²

where a = -0.2 bar^-1, b = 0.22 bar^-1, and c = 950 K². What is the value of the Boyle temperature of methane (in K)? (ln 1.1 = 0.095)

TestHub · Accepted Answer

At the Boyle temperature the second virial coefficient vanishes: B = 0, so a + b e −c/T² = 0, giving e −c/T² = -a/b = 0.2/0.22 = 1/1.1. Taking logarithms: -c/T 2 = -ln 1.1 = -0.095, so T 2 = c/0.095 = 950/0.095 = 10000 and T = 100 K. Hence the Boyle temperature is 0100 K.

Chemistry - Real Gas Question with Solution | TestHub

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