Chemistry - Real Gas Question with Solution | TestHub
ChemistryReal GasLiquification & Critical Constants of GasesMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
The equation of state for a gas is: P = RT/(V − b) − a/(T·V2), where V is the molar volume of the gas and a and b are constants different than van der Waal's constant.
The temperature above which the gas cannot be liquefied at any pressure, is
Options:
Answer:
D
Solution:
At the critical point (partial P/partial V)T = 0 and (partial2 P/partial V2)T = 0. First: RT/(V-b)2 = 2a/(TV3); second: 2RT/(V-b)3 = 6a/(TV4). Dividing gives Vc = 3b. Substituting back: RTc2(3b)3 = 2a(2b)2, i.e. Tc2 = 8a/(27Rb), so Tc = √(8a/27Rb). This is the critical temperature, above which liquefaction is impossible. Hence Ans (d).
Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Liquification & Critical Constants of Gases
⏱ 2mℹ️ Source: QB
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