Chemistry - Real Gas Question with Solution | TestHub
ChemistryReal GasVander Waal's Gas EquationMedium2 minQB
ChemistryMediuminteger
The van der Waal's constants a and b for a gas of molar mass 44.0 g/mol are 2.25 atm-L²/mol² and 0.04 L/mol, respectively. The density (in kg/m³) of the gas at 5 atm and 400 K is
Answer:
7
Solution:
(P + a/Vₘ²)(Vₘ - b) = RT, RT = 0.0821 × 400 = 32.84 L-atm/mol.
(5 + 2.25/Vₘ²)(Vₘ - 0.04) = 32.84.
Trial Vₘ = 6.54 L: (5 + 2.25/42.77)(6.50) = (5.0526)(6.50) = 32.84. So Vₘ = 6.54 L/mol.
Density = 44.0 g / 6.54 L = 6.73 g/L ≈ 7 kg/m³.
Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Vander Waal's Gas Equation
⏱ 2mℹ️ Source: QB
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