The second virial coefficient of a gas can be approximated by the empirical equation:
B = a + b·e^-c/T²
where a = -0.25 bar⁻¹, b = 0.275 bar⁻¹, and c = 3800 K². What is the value of the Boyle temperature of the gas (in K)? (ln 1.1 = 0.095)

Question

The second virial coefficient of a gas can be approximated by the empirical equation:

B = a + b·e^-c/T²

where a = -0.25 bar⁻¹, b = 0.275 bar⁻¹, and c = 3800 K². What is the value of the Boyle temperature of the gas (in K)? (ln 1.1 = 0.095)

TestHub · Accepted Answer

At the Boyle temperature, B = 0: a + b e -c/T² = 0, so e -c/T² = -a/b = 0.25/0.275 = 1/1.1. Taking logarithms: -c/T² = -ln 1.1 = -0.095, so T² = 3800/0.095 = 40000 and T = 200 K. Hence the Boyle temperature is 0200 K.

Chemistry - Real Gas Question with Solution | TestHub

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