At moderate pressure, the compressibility factor of a gas is given as Z = 1 + 0.40 P − ( 252/ T ) P , where P is in atm and T is in kelvin. What is the Boyle temperature of the gas?

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TestHub · Accepted Answer

At the Boyle temperature the coefficient of P is zero: $0.40 - 252/ T_{B} = 0$ .

$T_{B} = 252/0.40 = 630 K$ .

( 1008 K comes from using 0.25 instead of 0.40; 1.6 K from inverting the ratio.)

Answer: (C).

Chemistry - Real Gas Question with Solution | TestHub

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