The specific volume of N 2 gas at 100 atm is 0.0125 L / g . Taking N 2 as a van der Waals gas with a = 1.39 atm L 2 mol − 2 and b = 0.0391 L / mol , its temperature is approximately ( R = 0.0821 L

Question

The specific volume of N 2 ​ gas at 100 atm is 0.0125 L / g . Taking N 2 ​ as a van der Waals gas with a = 1.39 atm L 2 mol − 2 and b = 0.0391 L / mol , its temperature is approximately ( R = 0.0821 L atm K − 1 mol − 1 )

TestHub · Accepted Answer

V m ​ = 0.0125 L / g × 28 g / mol = 0.350 L / mol . a / V m 2 ​ = 1.39/0.1225 = 11.35 atm , so P + a / V m 2 ​ = 111.35 atm . V m ​ − b = 0.350 − 0.0391 = 0.3109 L . T = 111.35 × 0.3109/0.0821 = 421.7 K , about 422 K. Traps: leaving out a / V m 2 ​ gives 379 K; leaving out both corrections gives 426 K; 149 K is the value in °C. Answer: (C).

Chemistry - Real Gas Question with Solution | TestHub

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