Chemistry - Real Gas Question with Solution | TestHub
ChemistryReal GasLiquification & Critical Constants of GasesEasy2 minQB
ChemistryEasysingle choice
Passage / Comprehension
The equation of state for one mole of a gas is: P = RT/(V − b) − a/(T·V²), where V is the molar volume and a and b are constants different from van der Waals constants.
The minimum pressure needed for liquefaction of the gas at the temperature calculated above is
Options:
Answer:
D
Solution:
Pc = RTc/2b - a/(9b²Tc) with Tc = √(8a/27Rb), Vc = 3b. The two terms are (√(6))/9√(aR/b³) and (√(6))/12√(aR/b³), so Pc = (√(6))/36√(aR/b³) = √(aR/216b³). Hence Ans (d).
Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Liquification & Critical Constants of Gases
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
