Chemistry - Real Gas Question with Solution | TestHub

First, calculate the number of moles ($n$):

$n=\frac{64}{32}=2mol$

The given volume is $V=5L$.

Next, calculate the pressure correction using the formula $a{n}^2/V^2$:

Pressure correction $=1.0\times \frac{2^2}{5^2}=1.0\times \frac{4}{25}=0.16atm$ (This corresponds to Q).

Then, calculate the volume correction (excluded volume) using the formula $nb$:

Volume correction $=2\times 0.04=0.08L$ (This corresponds to S).

The ideal (free) volume is calculated as $V-nb$:

Ideal (free) volume $=5-0.08=4.92L$ (This corresponds to R).

Since $b=4\times actualmolecularvolumepermole$, the actual volume occupied by molecules is $nb/4$:

Actual volume occupied by molecules $=\frac{0.08}{4}=0.02L$ (This corresponds to P).

Therefore, the correct matches are: A$\to$Q; B$\to$R; C$\to$P; D$\to$S.