For one mole of a van der Waal's gas when b = 0 and T = 300 K , the PV vs, 1/ V plot is shown below. The value of the van der Waal's constant a (atm. liter 2 mol − 2 ) is :

Question

TestHub · Accepted Answer

( P + V 2 a ​ ) ( V ) = RT P V + a / V = RT ; P V = RT − a ( V ) y = RT − a ( x ) ​ So, slope = a = 3 − 2 21.6 − 20.1 ​ = 1 1.5 ​ = 1.5

Chemistry - Real Gas Question with Solution | TestHub

Options:

Doubts & Discussion