Chemistry - Real Gas Question with Solution | TestHub
ChemistryReal GasLiquification & Critical Constants of GasesMedium2 minQB
ChemistryMediummultiple choice
The van der Waal's equation for a real gas may be rearranged to give
Vm3 − (b + RT/P)Vm2 − (a/P)Vm − ab/P = 0
where Vm is the molar volume of the gas. Indicate the correct statement(s) amongst the following:
Options:(select one or more)
Answer:
A, B, C
Solution:
The cubic in Vm has: above Tc one real root and two imaginary roots (a ✓); exactly at Tc three coincident real roots (Vm = Vc, the critical point) (b ✓); below Tc three real roots (the largest and smallest corresponding to vapour and liquid) (c ✓). Statement (d) is therefore wrong. Hence (a), (b), (c).
Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Liquification & Critical Constants of Gases
⏱ 2mℹ️ Source: QB
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