Chemistry - Real Gas Question with Solution | TestHub
ChemistryReal GasLiquification & Critical Constants of GasesMedium2 minQB
ChemistryMediumsingle choice
The critical pressure and temperature of a van der Waal gas are 41.05 atm and 128 K, respectively. The critical volume of the gas is
Options:
Answer:
A
Solution:
b = (RTC)/(8PC) = (0.0821 × 128)/(8 × 41.05) = 10.51/328.4 = 0.032 l mol-1, and VC = 3b = 3 × 0.032 = 0.096 l/mol. Ans: (a)
Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Liquification & Critical Constants of Gases
⏱ 2mℹ️ Source: QB
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