Chemistry - Real Gas Question with Solution | TestHub
ChemistryReal GasCompressibility FactorHard2 minQB
ChemistryHardmultiple choice
For a van der Waals gas, a = 3.6 atm- and b = 0.03 L/mol. Select the correct possible graph(s)
[Given : R = 0.08 L-atm/mol-K]
Options:(select one or more)
Answer:
A, C
Solution:
Boyle temperature = a/(Rb) = 3.6/(0.08 × 0.03) = 1500 K.
Above , Z rises from 1.0 straight away (repulsion dominates). At the initial slope is zero and Z then rises. Below , Z first dips below 1.0.
(A) 2500 K > : monotonic rise, correct.
(B) 800 K < should show a dip first: incorrect.
(C) 1500 K = : flat start, then rise: correct.
(D) At , Z cannot fall below 1.0: incorrect.
Answer: (A), (C).
Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Compressibility Factor
⏱ 2mℹ️ Source: QB
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