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ChemistryReal GasCompressibility FactorMedium2 minQB

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At low pressure, the compressibility factor of a gas can be given as

Answer:

Solution:

Vander Waals' equation for one mole of gas is given by:

$(P + \frac{a}{V ^{2}}) (V - b) = RT$

At low pressure ( $P$ ), the volume ( $V$ ) is high, so $V - b \approx V$ .

Therefore, the equation simplifies to:

$(P + \frac{a}{V ^{2}}) V = RT$

$P V + \frac{a}{V} = RT$

$P V = RT - \frac{a}{V}$

The compressibility factor, $Z$ , is given by:

$Z = \frac{P V}{RT} = \frac{RT - \frac{a}{V}}{RT} = 1 - \frac{a}{RT V}$

Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Compressibility Factor

⏱ 2mℹ️ Source: QB

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