For real gases, the relation between P, V and T is given by van der Waals equation, $(P + \frac{a n^{2}}{V^{2}}) (V - n b) = n R T .$ For the following gases $C H_{4}, C O_{2}, O_{2}, H_{2}$ which gas will have
(i) highest value of 'a' and (ii) lowest value of 'b' respectively?

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TestHub · Accepted Answer

(i) Order of intermolecular attraction is $C O_{2} > C H_{4} > O_{2} > H_{2}$
In $C O_{2}$ value of 'a' will be maximum
(ii) Size increases in order of $H_{2} < O_{2} < C H_{4} < C O_{2}$
Hence, $H_{2}$ will have lowest value of 'b'.

Chemistry - Real Gas Question with Solution | TestHub

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