Chemistry - Real Gas Question with Solution | TestHub

ChemistryReal GasLiquification & Critical Constants of GasesEasy2 minQB
ChemistryEasysingle choice
Passage / Comprehension

The van der Waals equation was proposed in 1873. It was a first step towards taking into account interaction forces between real gas molecules. The perfect-gas equation refers to point-like particles which do not interact with one another. The b correction accounts for real gas molecules moving in only part of the occupied volume, obtained by subtracting the molecules’ own volume. The correction , proportional to the square of density, accounts for attraction between gas molecules. At the critical point, and . The equation can be made dimensionless using . In these coordinates, .

A van der Waals gas has atm and L/mol. Find in atm L²/mol².

Options:

Answer:
B
Solution:

The van der Waals critical conditions give V_c=3b and P_c=a/(27b²). Hence a=3P_cV_c²=3×70×0.183²=7.03 atm L² mol⁻², approximately 7, B.

Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Liquification & Critical Constants of Gases
⏱ 2mℹ️ Source: QB

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