Chemistry - PERIODIC TABLE Question with Solution | TestHub

Electronic configuration of element with atomic number 118 will be $[\mathrm{Rn}]5{\mathrm{f}}^{14}6{\mathrm{d}}^{10}$ $7{\mathrm{s}}^{2}7{\mathrm{p}}^6.$ Since its elctronic configuration in the outer moot or bit (ns ${}^{2}n{p}^6$ ) resemble with that of inert or noble gases, therefore it will be noble gas element.