Chemistry - PERIODIC TABLE Question with Solution | TestHub

Ionization Enthalpy values indicate that the metal belongs to${\mathrm{I}}^{\mathrm{st}}$group, since the second ionization enthalpy is very high.
(Q - only one valence electron)
Metal hydroxide will be of the type,$\mathrm{MOH}$.

$\underset{\left(1\text{mol}\right)}{\text{MOH}}+\underset{\left(1\text{mol}\right)}{\text{HCl}}\to \text{MCl}+{\text{H}}_{\text{2}}\text{O}$

$\text{MOH}+\frac{1}{2}{\text{H}}_2{\text{SO}}_4\to \frac{1}{2}{\text{M}}_2{\text{SO}}_4+{\text{H}}_2\text{O}$

$(1\text{mol})\left(\frac{1}{2}\text{mol}\right)$So, one mole of$\mathrm{HCl}$is required to react with one mole of$\mathrm{MOH}$.

So,$\frac{1}{2}$mole of${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$is required to react with one mole of$\mathrm{MOH}$.