Chemistry - PERIODIC TABLE Question with Solution | TestHub

$\mathrm{Be}\to 1{\mathrm{s}}^2{\mathrm{Be}}^{-}\to 1{\mathrm{s}}^2,2{\mathrm{s}}^2,2{\mathrm{p}}^1$

(a) ${\mathrm{IE}}_1$ of $\mathrm{Be}>\mathrm{I}.{\mathrm{E}}_1$ of ${\mathrm{Be}}^{-}$

(c) ${\mathrm{Be}}^{-}(\mathrm{g})\to \mathrm{Be}(\mathrm{g})+{\mathrm{e}}^{-}$ I. ${\mathrm{E}}_1\&{\mathrm{Be}}^{-}$

${\mathrm{Be}}^{-}(\mathrm{g})\to {\mathrm{Be}}^{-}(\mathrm{g})$ E.A. of Be

$\mid {\mathrm{IE}}_1$ of ${\mathrm{Be}}^{-}=\mid$E.A. of $\mathrm{Be}\Vert$

(d) $I{E}_1$ of $Be>I{E}_1$ of $B$

due to paired ${\mathrm{e}}^{-}$present in Be