Chemistry - Nomenclature Question with Solution | TestHub

Ans. (I) → (R), (II) → (T), (III) → (P), (IV) → (S)

(I) $\to$ (R): Numbering gives the alkene bond priority, resulting in 3,3-Dimethyl cyclohexene.

(II) $\to$ (T): The ring is numbered to give the double bond and methyl groups the lowest possible locants, making it 1,6-Dimethyl cyclohexene.

(III) $\to$ (P): Substituents are numbered alphabetically (Bromo before Chloro), giving 1-Bromo-3-chlorocyclopentane.

(IV) $\to$ (S): The principal alcohol (-OH) functional group gets position 1, naming it Cyclopentanol.