The percentage of C, H and N in an organic compound are 40%, 13.3% and 46.7% respectively then empirical formula is

Question

TestHub · Accepted Answer

Element	%	Atomic mass	Relative number of atoms	Simplest ratio of atoms	Element
1.	C	40	12	$\frac{40}{12} = 3.33$	$\frac{3.33}{3.3} = 1$
2.	H	13.3	1	$\frac{13.3}{1} = 13.3$	$\frac{13.3}{3.3} = 4$
3.	N	46.7	14	$\frac{46.7}{14} = 3.3$	$\frac{3.3}{3.3} = 1$

Therefore, empirical formula is $C H_{4} N$ .

Chemistry - Nomenclature Question with Solution | TestHub