How many electrons are present in 2 × 1 0 − 3 mole of O − 2 ions :-

No. of electrons in one O − 2 ion = 8 + 2 = 10 No. of O − 2 ions in 2 × 1 0 − 3 mole = 2 × 1 0 − 3 × 6.02 × 1 0 23 = 12.04 × 1 0 20 ≃ 1.2 × 1 0 21 Therefore, total no. of O − 2 ions = 1.2 × 1 0 21 × 10 = 1.2 × 1 0 22

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How many electrons are present in $2 \times 1 0^{- 3}$ mole of $O^{- 2}$ ions :-

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Answer:

Solution:

No. of electrons in one $O^{- 2}$ ion $= 8 + 2 = 10$

No. of $O^{- 2}$ ions in $2 \times 1 0^{- 3}$ mole

$= 2 \times 1 0^{- 3} \times 6.02 \times 1 0^{23}$

$= 12.04 \times 1 0^{20}$

$≃ 1.2 \times 1 0^{21}$

Therefore, total no. of $O^{- 2}$ ions

$= 1.2 \times 1 0^{21} \times 10$

$= 1.2 \times 1 0^{22}$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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