Chemistry - Mole Concept Question with Solution | TestHub

$Ca{\left(N{O}_3\right)}_2+N{a}_2{C}_2{O}_4\to 2NaN{O}_3+Ca{C}_2{0}_4$

100 mL of 0.06 M Ca(NO₃)₂ contains $100\times 0.06=6$ millimoles.

50 mL of 0.06 M Na₂C₂O₄ contains $50\times 0.06=3$ millimoles.

3 millimoles of C₂O₄²⁻ will react with 3 millimoles of Ca²⁺.

For 3 millimoles of CaC₂O₄ =$\frac{3}{1000}=0.003moles$

Thus, (a) is correct.

Excess Ca²⁺ left = $6-3=3$ millimoles =$\frac{3}{1000}=0.003moles$

Thus, (c) is correct because sodium oxalate is present in a smaller amount than required.

(d) is correct because Ca(NO₃)₂ is present in a larger amount.