Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptCalculation of moleMedium2 minQB

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Dissolving 120 g of urea (mol. wt. 60) in 1000 g of water gave a solution of density $1.15 g / mL$ . The molarity of the solution is :

Answer:

Solution:

Mass of solution $= 120 + 1000 = 1120 g$

Volume of solution $= \frac{1120}{1.15} mL$ $\frac{1120}{1.15} mL$

solution contains $= \frac{120}{60} = 2$ mole solute

1000 mL solution contains $= \frac{2 \times 1000 \times 1.15}{1120} = 2.05 M$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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