2.0 g of a bromo hydrocarbon (X) was subjected to Carius analysis, gave 3.36 g of AgBr. The percentage of carbon in the compound (X) is 26.7%. Total number of carbon atoms in the empirical formula for compound (X) is $____$ .
(Given molar mass in g mol^-1 H : 1, C : 12, Br : 80, Ag : 108)

Question

2.0 g of a bromo hydrocarbon (X) was subjected to Carius analysis, gave 3.36 g of AgBr. The percentage of carbon in the compound (X) is 26.7%. Total number of carbon atoms in the empirical formula for compound (X) is $____$ .

(Given molar mass in g mol^-1 H : 1, C : 12, Br : 80, Ag : 108)

TestHub · Accepted Answer

n B r ​ = 108 + 80 3.36 ​ r = n o . o f B r a t o m s in or g ani cco m p o u n d n or g ani cco m p o u n d ​ = ( 108 + 80 ) × x 3.36 ​ = M 2 ​ M = 3.36 2 × 188 × x ​ M = 2 1 ​ × x ( x is an integer) W C ​ = 100 112 × x × 26.7 ​ = 30 × x n C ​ = 12 30 × x ​ = 2.5 × x Take x = 2 , n C ​ = 5 . (Empirical formula is C 5 ​ H 4 ​ B r )

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