Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptLaws of Chemical CalculationsMedium2 minQB

ChemistryMediumsingle choice

2.76 g of silver carbonate on being strongly heated yields a residue weighing

Answer:

Solution:

Ag₂CO₃(s) $⟶$ 2Ag(s) + CO₂(g) + ½O₂(g)

Moles before reaction: $\frac{2.76}{276} = 0.01$ 0 0 0

After reaction: 0 0.02

Weight of Ag (Residue) is $0.02 \times 108 = 2.16$ g.

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Laws of Chemical Calculations

⏱ 2mℹ️ Source: QB

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