Chemistry - Mole Concept Question with Solution | TestHub

Question Explanation: Match the column

Match the column.

Concept: This question is based on the calculation of moles.

Solution:

moles moles

(number of molecules) (number of atoms)

(1) ${\mathrm{NH}}_3=\frac{4.25}{17}=0.25(0.25{\mathrm{N}}_{\mathrm{A}})$ $0.25\times 4=1({\mathrm{N}}_{\mathrm{A}})$

$H_{2}O=\frac{4.5}{18}=0.25\left(0.25{\mathrm{N}}_{\mathrm{A}}\right)$ $0.25\times 3=0.75\left(0.75{\mathrm{N}}_{\mathrm{A}}\right)$

(2)${\mathrm{CO}}_2=\frac{2.2}{44}=0.05(0.05{\mathrm{N}}_{\mathrm{A}})$ $0.05\times 3=0.15(0.15{\mathrm{N}}_{\mathrm{A}})$

$H_{2}O=\frac{0.90}{18}=0.05\left(0.05{\mathrm{N}}_{\mathrm{A}}\right)$ $0.05\times 3=0.15\left(0.15{\mathrm{N}}_{\mathrm{A}}\right)$

(3)${\mathrm{CH}}_3\mathrm{Cl}=\frac{4}{50.5}=0.079(0.079{\mathrm{N}}_{\mathrm{A}})0.079\times 5=0.395(0.395{\mathrm{N}}_{\mathrm{A}})$

${\mathrm{NH}}_3=\frac{5}{17}=0.294\left(0.294{\mathrm{N}}_{\mathrm{A}}\right)$ $0.294\times 4=1.176\left(1.176{\mathrm{N}}_{\mathrm{A}}\right)$

(4)${\mathrm{O}}_3=\frac{3.2}{48}=0.067(0.067{\mathrm{N}}_{\mathrm{A}})$ $0.067\times 3=0.201(0.201{\mathrm{N}}_{\mathrm{A}})$

$\mathrm{CO}=\frac{2.8}{28}=0.1\left(0.1{\mathrm{N}}_{\mathrm{A}}\right)$ $0.1\times 2=0.2\left(0.2{\mathrm{N}}_{\mathrm{A}}\right)$

P → 2,4 ; Q →  1,2 ; R →  2 ; S →  3