The number of atoms in 0.1 mole of a triatomic gas is ( N A = 6.02 × 1 0 23 mol − 1 ) NEET 2010 (Screening)

Number of atoms = number of moles × N A × atomicity = 0.1 × 6.02 × 1 0 23 × 3 = 1.806 × 1 0 23 atoms

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ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2010

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The number of atoms in 0.1 mole of a triatomic gas is $(N_{A} = 6.02 \times 1 0^{23} mol^{- 1})$ NEET 2010 (Screening)

Answer:

Solution:

Number of atoms $=$ number of moles $\times N_{A} \times$ atomicity $= 0.1 \times 6.02 \times 1 0^{23} \times 3 = 1.806 \times 1 0^{23} atoms$

Stream:NEETSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2010

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