What is the empirical formula of vanadium oxide if 2.74 g of metal oxide contains 1.53 g of metal?
Given: Take atomic mass of vanadium as $52 g/mol .$

Question

What is the empirical formula of vanadium oxide if 2.74 g of metal oxide contains 1.53 g of metal? Given: Take atomic mass of vanadium as 52 g/mol .

TestHub · Accepted Answer

% of V = 1.53 2.74 × 100 = 55.83 So % of O = 44.17 Element % Atomic ratio Simplest ratio V 55.83 55.83 52 = 1.1 1.1 1.1 = 1 O 44.17 44.17 16 = 2.76 2.76 1.1 = 2.5 V : O = 2: 5 Thus, empirical formula = V 2 O 5

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Doubts & Discussion

Element	%	Atomic ratio	Simplest ratio
V	55.83	$\frac{55.83}{52} = 1.1$	$\frac{1.1}{1.1} = 1$
O	44.17	$\frac{44.17}{16} = 2.76$	$\frac{2.76}{1.1} = 2.5$