To obtain maximum mass of NO 2 from a given mass of a mixture of NH 3 and O 2 , the ratio of mass of NH 3 to O 2 should be 2 N H 3 + 2 7 O 2 → 2 N O 2 + 3 H 2 O

Question

To obtain maximum mass of NO 2 ​ from a given mass of a mixture of NH 3 ​ and O 2 ​ , the ratio of mass of NH 3 ​ to O 2 ​ should be 2 N H 3 ​ + 2 7 ​ O 2 ​ → 2 N O 2 ​ + 3 H 2 ​ O

TestHub · Accepted Answer

To maximize NO₂ yield, reactants must be in stoichiometric ratio.

Balanced equation: $2 NH_{3} + \frac{7}{2} O_{2} \to 2 NO_{2} + 3 H_{2} O$

From the equation, 2 moles of NH₃ react with 3.5 moles of O₂.

Mass of NH₃ = $2 m o l \times 17 g / m o l = 34 g$

Mass of O₂ = $3.5 m o l \times 32 g / m o l = 112 g$

Ratio of mass of NH₃ to O₂ = $\frac{M a sso f N H _{3}}{M a sso f O _{2}} = \frac{34 g}{112 g} = \frac{17}{56}$

Chemistry - Mole Concept Question with Solution | TestHub

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