Mass of magnesium required to produce 220 mL of hydrogen gas at STP on reaction with excess of dil. HCl is
Given : Molar mass of Mg is $24 g mol^{- 1}$ .

Question

Mass of magnesium required to produce 220 mL of hydrogen gas at STP on reaction with excess of dil. HCl is Given : Molar mass of Mg is 24 g mol − 1 .

TestHub · Accepted Answer

Mg + 2 HCl → MgCl 2 ​ + H 2 ​ Volume H 2 ​ evolved = 220 ml Mole of H 2 ​ = 22.4 220 × 1 0 − 3 ​ = mole of Mg used ∴ Mass of Mg used ​ = 22.4 220 × 1 0 − 3 ​ × 24 = 235.7 × 1 0 − 3 gm = 235.7 mg ​

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