Chemistry - Mole Concept Question with Solution | TestHub

${\mathrm{C}}_{\mathrm{x}}{\mathrm{H}}_{\mathrm{y}}{\mathrm{O}}_{\mathrm{z}}+\left(\mathrm{x}+\frac{\mathrm{y}}{4}-\frac{\mathrm{z}}{2}\right){\mathrm{O}}_2\to {\mathrm{xCO}}_2+\frac{\mathrm{y}}{2}{\mathrm{H}}_2\mathrm{O}$

$0.3\mathrm{g}0.2\mathrm{g}0.1\mathrm{g}$

$\frac{{\mathrm{n}}_{{\mathrm{CO}}_2}}{{\mathrm{n}}_{{\mathrm{H}}_2\mathrm{O}}}=\frac{\mathrm{x}}{\mathrm{y}/2}=\frac{0.2/44}{.1/18}$

$\frac{2x}{y}=\frac{36}{44}=\frac{9}{11}$

$\mathrm{x}=\frac{9\mathrm{y}}{22}$

$\frac{{\mathrm{n}}_{{\mathrm{C}}_{\mathrm{x}}{\mathrm{H}}_{\mathrm{y}}{\mathrm{O}}_{\mathrm{z}}}}{{\mathrm{nCO}}_2}=\frac{1}{\mathrm{x}}$

$\frac{0.3}{12x+y+16z}\times \frac{44}{0.2}\times \frac{1}{x}$

$66\mathrm{x}=12\mathrm{x}+\mathrm{y}+16\mathrm{z}$

$54\mathrm{x}=\mathrm{y}+16\mathrm{z}$

$\frac{54\times 9y}{22}-y=16z$

$\frac{464\mathrm{y}}{22}=16\mathrm{z}$

$\mathrm{z}=\frac{29\mathrm{y}}{22}$

${\mathrm{C}}_{\mathrm{x}}{\mathrm{H}}_{\mathrm{y}}{\mathrm{O}}_{\mathrm{z}}={\mathrm{C}}_{\mathrm{x}}{\mathrm{H}}_{\mathrm{y}}{\mathrm{O}}_{\mathrm{z}}$

${\mathrm{C}}_{\frac{9y}{22}}{\mathrm{H}}_y{\mathrm{O}}_{\frac{29y}{22}}$

${\mathrm{C}}_9^{\underline{22}}{\mathrm{H}}_{22}{\mathrm{O}}_{29}^{\underline{22}}$

$\%$ of $\mathrm{C}=\frac{12\times 9}{(12\times 9+22+29\times 16)}\times 100=\frac{108}{594}\times 100$

18.18%