Chemistry - Mole Concept Question with Solution | TestHub

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Density of 3 M NaCl solution is $1.25 g / mL$ . The molality of the solution is :

Answer:

Solution:

$3 M NaCl, d_{sol} = 1.25 gm / mol$

$Molality = \frac{M \times 1000}{1000 d - M \times M _{W}} = \frac{3000}{1250 - 175.5} = 2.79$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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