Chemistry - Mole Concept Question with Solution | TestHub

$\mathrm{density}=\frac{\mathrm{mass}}{\mathrm{volume}}$

mass of ${\mathrm{C}}_{15}{\mathrm{H}}_{30}=\mathrm{d}\times \mathrm{V}=0.756\times 1000=756 \mathrm{gram}$

${\mathrm{C}}_{15}{\mathrm{H}}_{30}\left(\mathrm{l}\right)+\frac{45}{2}{\mathrm{O}}_2\left(\mathrm{g}\right)⟶15{\mathrm{CO}}_2\left(\mathrm{g}\right)+15{\mathrm{H}}_2\mathrm{O}$

$$\begin{gathered} \mathrm{Moles} \mathrm{of} {\mathrm{C}}_{15}{\mathrm{H}}_{30} = \frac{756}{210} \\ \mathrm{Moles} \mathrm{of} {\mathrm{O}}_2 \mathrm{used}= \frac{45}{2}\left[\frac{756}{210}\right] \mathrm{mole} \\ \mathrm{Moles} \mathrm{of} {\mathrm{CO}}_2 \mathrm{formed}=15\left[\frac{756}{210}\right] \end{gathered}$$

${\mathrm{W}}_{{\mathrm{O}}_2}=\frac{45}{2}\left[\frac{756}{210}\right]32=2592 \mathrm{gram}$

${\mathrm{W}}_{{\mathrm{CO}}_2}=2376 \mathrm{gram}$