Chemistry - Mole Concept Question with Solution | TestHub

Meq of H₂SO₄ used by NH₃ = $12.5\times 1\times 2=25$

Percentage of N in the compound:

$$\frac{25\times 10^{-3}\times 14\times 100}{0.55}=63.6$$

Alternatively, Meq. of H₂SO₄ = Meq. of NH₃.

$12.5\times 1\times 2=25$ meq. of NH₃.

This equals 25 millimoles of NH₃.

So, millimoles of 'N' = 25.

Moles of 'N' = $25\times 10^{-3}$.

Weight of N = $14\times 25\times 10^{-3}$.

Percentage of N = $\frac{14\times 25\times 10^{-3}}{0.55}\times 100$.

$=63.66\approx 64\%$.